Optimal. Leaf size=189 \[ -\frac {e}{\left (a d^2-b d e+c e^2\right ) (d+e x)}-\frac {\left (2 a^2 d^2+b^2 e^2-2 a e (b d+c e)\right ) \tanh ^{-1}\left (\frac {b+2 a x}{\sqrt {b^2-4 a c}}\right )}{\sqrt {b^2-4 a c} \left (a d^2-e (b d-c e)\right )^2}+\frac {e (2 a d-b e) \log (d+e x)}{\left (a d^2-e (b d-c e)\right )^2}-\frac {e (2 a d-b e) \log \left (c+b x+a x^2\right )}{2 \left (a d^2-e (b d-c e)\right )^2} \]
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Rubi [A]
time = 0.21, antiderivative size = 189, normalized size of antiderivative = 1.00, number of steps
used = 8, number of rules used = 7, integrand size = 25, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.280, Rules used = {1583, 723, 814,
648, 632, 212, 642} \begin {gather*} -\frac {\left (2 a^2 d^2-2 a e (b d+c e)+b^2 e^2\right ) \tanh ^{-1}\left (\frac {2 a x+b}{\sqrt {b^2-4 a c}}\right )}{\sqrt {b^2-4 a c} \left (a d^2-e (b d-c e)\right )^2}-\frac {e}{(d+e x) \left (a d^2-b d e+c e^2\right )}-\frac {e (2 a d-b e) \log \left (a x^2+b x+c\right )}{2 \left (a d^2-e (b d-c e)\right )^2}+\frac {e (2 a d-b e) \log (d+e x)}{\left (a d^2-e (b d-c e)\right )^2} \end {gather*}
Antiderivative was successfully verified.
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Rule 212
Rule 632
Rule 642
Rule 648
Rule 723
Rule 814
Rule 1583
Rubi steps
\begin {align*} \int \frac {1}{\left (a+\frac {c}{x^2}+\frac {b}{x}\right ) x^2 (d+e x)^2} \, dx &=\int \frac {1}{(d+e x)^2 \left (c+b x+a x^2\right )} \, dx\\ &=-\frac {e}{\left (a d^2-b d e+c e^2\right ) (d+e x)}+\frac {\int \frac {a d-b e-a e x}{(d+e x) \left (c+b x+a x^2\right )} \, dx}{a d^2-b d e+c e^2}\\ &=-\frac {e}{\left (a d^2-b d e+c e^2\right ) (d+e x)}+\frac {\int \left (\frac {e^2 (2 a d-b e)}{\left (a d^2-e (b d-c e)\right ) (d+e x)}+\frac {a^2 d^2+b^2 e^2-a e (2 b d+c e)-a e (2 a d-b e) x}{\left (a d^2-e (b d-c e)\right ) \left (c+b x+a x^2\right )}\right ) \, dx}{a d^2-b d e+c e^2}\\ &=-\frac {e}{\left (a d^2-b d e+c e^2\right ) (d+e x)}+\frac {e (2 a d-b e) \log (d+e x)}{\left (a d^2-e (b d-c e)\right )^2}+\frac {\int \frac {a^2 d^2+b^2 e^2-a e (2 b d+c e)-a e (2 a d-b e) x}{c+b x+a x^2} \, dx}{\left (a d^2-e (b d-c e)\right )^2}\\ &=-\frac {e}{\left (a d^2-b d e+c e^2\right ) (d+e x)}+\frac {e (2 a d-b e) \log (d+e x)}{\left (a d^2-e (b d-c e)\right )^2}-\frac {(e (2 a d-b e)) \int \frac {b+2 a x}{c+b x+a x^2} \, dx}{2 \left (a d^2-e (b d-c e)\right )^2}+\frac {\left (2 a^2 d^2+b^2 e^2-2 a e (b d+c e)\right ) \int \frac {1}{c+b x+a x^2} \, dx}{2 \left (a d^2-e (b d-c e)\right )^2}\\ &=-\frac {e}{\left (a d^2-b d e+c e^2\right ) (d+e x)}+\frac {e (2 a d-b e) \log (d+e x)}{\left (a d^2-e (b d-c e)\right )^2}-\frac {e (2 a d-b e) \log \left (c+b x+a x^2\right )}{2 \left (a d^2-e (b d-c e)\right )^2}-\frac {\left (2 a^2 d^2+b^2 e^2-2 a e (b d+c e)\right ) \text {Subst}\left (\int \frac {1}{b^2-4 a c-x^2} \, dx,x,b+2 a x\right )}{\left (a d^2-e (b d-c e)\right )^2}\\ &=-\frac {e}{\left (a d^2-b d e+c e^2\right ) (d+e x)}-\frac {\left (2 a^2 d^2+b^2 e^2-2 a e (b d+c e)\right ) \tanh ^{-1}\left (\frac {b+2 a x}{\sqrt {b^2-4 a c}}\right )}{\sqrt {b^2-4 a c} \left (a d^2-e (b d-c e)\right )^2}+\frac {e (2 a d-b e) \log (d+e x)}{\left (a d^2-e (b d-c e)\right )^2}-\frac {e (2 a d-b e) \log \left (c+b x+a x^2\right )}{2 \left (a d^2-e (b d-c e)\right )^2}\\ \end {align*}
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Mathematica [A]
time = 0.15, size = 151, normalized size = 0.80 \begin {gather*} \frac {-\frac {2 e \left (a d^2+e (-b d+c e)\right )}{d+e x}+\frac {2 \left (2 a^2 d^2+b^2 e^2-2 a e (b d+c e)\right ) \tan ^{-1}\left (\frac {b+2 a x}{\sqrt {-b^2+4 a c}}\right )}{\sqrt {-b^2+4 a c}}-2 e (-2 a d+b e) \log (d+e x)+e (-2 a d+b e) \log (c+x (b+a x))}{2 \left (a d^2+e (-b d+c e)\right )^2} \end {gather*}
Antiderivative was successfully verified.
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Maple [A]
time = 0.30, size = 197, normalized size = 1.04
method | result | size |
default | \(-\frac {e}{\left (a \,d^{2}-d e b +c \,e^{2}\right ) \left (e x +d \right )}+\frac {e \left (2 a d -e b \right ) \ln \left (e x +d \right )}{\left (a \,d^{2}-d e b +c \,e^{2}\right )^{2}}+\frac {\frac {\left (-2 d e \,a^{2}+a b \,e^{2}\right ) \ln \left (a \,x^{2}+b x +c \right )}{2 a}+\frac {2 \left (a^{2} d^{2}-2 a b d e -a c \,e^{2}+e^{2} b^{2}-\frac {\left (-2 d e \,a^{2}+a b \,e^{2}\right ) b}{2 a}\right ) \arctan \left (\frac {2 a x +b}{\sqrt {4 a c -b^{2}}}\right )}{\sqrt {4 a c -b^{2}}}}{\left (a \,d^{2}-d e b +c \,e^{2}\right )^{2}}\) | \(197\) |
risch | \(\text {Expression too large to display}\) | \(12760\) |
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-2)]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Exception raised: ValueError} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [B] Leaf count of result is larger than twice the leaf count of optimal. 526 vs.
\(2 (197) = 394\).
time = 1.94, size = 1071, normalized size = 5.67 \begin {gather*} \left [-\frac {2 \, {\left (a b^{2} - 4 \, a^{2} c\right )} d^{2} e - 2 \, {\left (b^{3} - 4 \, a b c\right )} d e^{2} + {\left (2 \, a^{2} d^{3} + {\left (b^{2} - 2 \, a c\right )} x e^{3} - {\left (2 \, a b d x - {\left (b^{2} - 2 \, a c\right )} d\right )} e^{2} + 2 \, {\left (a^{2} d^{2} x - a b d^{2}\right )} e\right )} \sqrt {b^{2} - 4 \, a c} \log \left (\frac {2 \, a^{2} x^{2} + 2 \, a b x + b^{2} - 2 \, a c + \sqrt {b^{2} - 4 \, a c} {\left (2 \, a x + b\right )}}{a x^{2} + b x + c}\right ) + 2 \, {\left (b^{2} c - 4 \, a c^{2}\right )} e^{3} + {\left (2 \, {\left (a b^{2} - 4 \, a^{2} c\right )} d^{2} e - {\left (b^{3} - 4 \, a b c\right )} x e^{3} + {\left (2 \, {\left (a b^{2} - 4 \, a^{2} c\right )} d x - {\left (b^{3} - 4 \, a b c\right )} d\right )} e^{2}\right )} \log \left (a x^{2} + b x + c\right ) - 2 \, {\left (2 \, {\left (a b^{2} - 4 \, a^{2} c\right )} d^{2} e - {\left (b^{3} - 4 \, a b c\right )} x e^{3} + {\left (2 \, {\left (a b^{2} - 4 \, a^{2} c\right )} d x - {\left (b^{3} - 4 \, a b c\right )} d\right )} e^{2}\right )} \log \left (x e + d\right )}{2 \, {\left ({\left (a^{2} b^{2} - 4 \, a^{3} c\right )} d^{5} + {\left (b^{2} c^{2} - 4 \, a c^{3}\right )} x e^{5} - {\left (2 \, {\left (b^{3} c - 4 \, a b c^{2}\right )} d x - {\left (b^{2} c^{2} - 4 \, a c^{3}\right )} d\right )} e^{4} + {\left ({\left (b^{4} - 2 \, a b^{2} c - 8 \, a^{2} c^{2}\right )} d^{2} x - 2 \, {\left (b^{3} c - 4 \, a b c^{2}\right )} d^{2}\right )} e^{3} - {\left (2 \, {\left (a b^{3} - 4 \, a^{2} b c\right )} d^{3} x - {\left (b^{4} - 2 \, a b^{2} c - 8 \, a^{2} c^{2}\right )} d^{3}\right )} e^{2} + {\left ({\left (a^{2} b^{2} - 4 \, a^{3} c\right )} d^{4} x - 2 \, {\left (a b^{3} - 4 \, a^{2} b c\right )} d^{4}\right )} e\right )}}, -\frac {2 \, {\left (a b^{2} - 4 \, a^{2} c\right )} d^{2} e - 2 \, {\left (b^{3} - 4 \, a b c\right )} d e^{2} + 2 \, {\left (2 \, a^{2} d^{3} + {\left (b^{2} - 2 \, a c\right )} x e^{3} - {\left (2 \, a b d x - {\left (b^{2} - 2 \, a c\right )} d\right )} e^{2} + 2 \, {\left (a^{2} d^{2} x - a b d^{2}\right )} e\right )} \sqrt {-b^{2} + 4 \, a c} \arctan \left (-\frac {\sqrt {-b^{2} + 4 \, a c} {\left (2 \, a x + b\right )}}{b^{2} - 4 \, a c}\right ) + 2 \, {\left (b^{2} c - 4 \, a c^{2}\right )} e^{3} + {\left (2 \, {\left (a b^{2} - 4 \, a^{2} c\right )} d^{2} e - {\left (b^{3} - 4 \, a b c\right )} x e^{3} + {\left (2 \, {\left (a b^{2} - 4 \, a^{2} c\right )} d x - {\left (b^{3} - 4 \, a b c\right )} d\right )} e^{2}\right )} \log \left (a x^{2} + b x + c\right ) - 2 \, {\left (2 \, {\left (a b^{2} - 4 \, a^{2} c\right )} d^{2} e - {\left (b^{3} - 4 \, a b c\right )} x e^{3} + {\left (2 \, {\left (a b^{2} - 4 \, a^{2} c\right )} d x - {\left (b^{3} - 4 \, a b c\right )} d\right )} e^{2}\right )} \log \left (x e + d\right )}{2 \, {\left ({\left (a^{2} b^{2} - 4 \, a^{3} c\right )} d^{5} + {\left (b^{2} c^{2} - 4 \, a c^{3}\right )} x e^{5} - {\left (2 \, {\left (b^{3} c - 4 \, a b c^{2}\right )} d x - {\left (b^{2} c^{2} - 4 \, a c^{3}\right )} d\right )} e^{4} + {\left ({\left (b^{4} - 2 \, a b^{2} c - 8 \, a^{2} c^{2}\right )} d^{2} x - 2 \, {\left (b^{3} c - 4 \, a b c^{2}\right )} d^{2}\right )} e^{3} - {\left (2 \, {\left (a b^{3} - 4 \, a^{2} b c\right )} d^{3} x - {\left (b^{4} - 2 \, a b^{2} c - 8 \, a^{2} c^{2}\right )} d^{3}\right )} e^{2} + {\left ({\left (a^{2} b^{2} - 4 \, a^{3} c\right )} d^{4} x - 2 \, {\left (a b^{3} - 4 \, a^{2} b c\right )} d^{4}\right )} e\right )}}\right ] \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] Timed out
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Timed out} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A]
time = 4.13, size = 331, normalized size = 1.75 \begin {gather*} -\frac {{\left (2 \, a^{2} d^{2} e^{2} - 2 \, a b d e^{3} + b^{2} e^{4} - 2 \, a c e^{4}\right )} \arctan \left (-\frac {{\left (2 \, a d - \frac {2 \, a d^{2}}{x e + d} - b e + \frac {2 \, b d e}{x e + d} - \frac {2 \, c e^{2}}{x e + d}\right )} e^{\left (-1\right )}}{\sqrt {-b^{2} + 4 \, a c}}\right ) e^{\left (-2\right )}}{{\left (a^{2} d^{4} - 2 \, a b d^{3} e + b^{2} d^{2} e^{2} + 2 \, a c d^{2} e^{2} - 2 \, b c d e^{3} + c^{2} e^{4}\right )} \sqrt {-b^{2} + 4 \, a c}} - \frac {{\left (2 \, a d e - b e^{2}\right )} \log \left (-a + \frac {2 \, a d}{x e + d} - \frac {a d^{2}}{{\left (x e + d\right )}^{2}} - \frac {b e}{x e + d} + \frac {b d e}{{\left (x e + d\right )}^{2}} - \frac {c e^{2}}{{\left (x e + d\right )}^{2}}\right )}{2 \, {\left (a^{2} d^{4} - 2 \, a b d^{3} e + b^{2} d^{2} e^{2} + 2 \, a c d^{2} e^{2} - 2 \, b c d e^{3} + c^{2} e^{4}\right )}} - \frac {e^{3}}{{\left (a d^{2} e^{2} - b d e^{3} + c e^{4}\right )} {\left (x e + d\right )}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [B]
time = 8.11, size = 1782, normalized size = 9.43 \begin {gather*} \frac {\ln \left (c\,e^4\,{\left (b^2-4\,a\,c\right )}^{5/2}-8\,b^5\,c\,e^4-8\,b^6\,e^4\,x-4\,a^3\,d^4\,{\left (b^2-4\,a\,c\right )}^{3/2}-4\,a^3\,b^3\,d^4+4\,b^3\,e^4\,x\,{\left (b^2-4\,a\,c\right )}^{3/2}+60\,a\,b^3\,c^2\,e^4-112\,a^2\,b\,c^3\,e^4+4\,a\,b^5\,d^2\,e^2-8\,a^2\,b^4\,d^3\,e+256\,a^3\,c^3\,d\,e^3-256\,a^4\,c^2\,d^3\,e-8\,a^4\,b^2\,d^4\,x+32\,a^3\,c^3\,e^4\,x+10\,b\,d\,e^3\,{\left (b^2-4\,a\,c\right )}^{5/2}+4\,b\,e^4\,x\,{\left (b^2-4\,a\,c\right )}^{5/2}+16\,a^4\,b\,c\,d^4+32\,a^5\,c\,d^4\,x-14\,a\,d^2\,e^2\,{\left (b^2-4\,a\,c\right )}^{5/2}+7\,b^2\,c\,e^4\,{\left (b^2-4\,a\,c\right )}^{3/2}-10\,b^3\,d\,e^3\,{\left (b^2-4\,a\,c\right )}^{3/2}-8\,a\,d\,e^3\,x\,{\left (b^2-4\,a\,c\right )}^{5/2}+24\,a\,b^4\,c\,d\,e^3+64\,a\,b^4\,c\,e^4\,x+32\,a\,b^5\,d\,e^3\,x-8\,a^2\,b\,d^3\,e\,{\left (b^2-4\,a\,c\right )}^{3/2}-32\,a^3\,d^3\,e\,x\,{\left (b^2-4\,a\,c\right )}^{3/2}+96\,a^3\,b^2\,c\,d^3\,e+16\,a^3\,b^3\,d^3\,e\,x+18\,a\,b^2\,d^2\,e^2\,{\left (b^2-4\,a\,c\right )}^{3/2}-160\,a^2\,b^2\,c^2\,d\,e^3-56\,a^2\,b^3\,c\,d^2\,e^2+160\,a^3\,b\,c^2\,d^2\,e^2-136\,a^2\,b^2\,c^2\,e^4\,x-40\,a^2\,b^4\,d^2\,e^2\,x-448\,a^4\,c^2\,d^2\,e^2\,x+48\,a^2\,b\,d^2\,e^2\,x\,{\left (b^2-4\,a\,c\right )}^{3/2}+272\,a^3\,b^2\,c\,d^2\,e^2\,x-64\,a^4\,b\,c\,d^3\,e\,x-24\,a\,b^2\,d\,e^3\,x\,{\left (b^2-4\,a\,c\right )}^{3/2}-240\,a^2\,b^3\,c\,d\,e^3\,x+448\,a^3\,b\,c^2\,d\,e^3\,x\right )\,\left (a\,\left (\left (2\,b\,c-c\,\sqrt {b^2-4\,a\,c}\right )\,e^2+\left (b^2\,d-b\,d\,\sqrt {b^2-4\,a\,c}\right )\,e\right )-e^2\,\left (\frac {b^3}{2}-\frac {b^2\,\sqrt {b^2-4\,a\,c}}{2}\right )+a^2\,\left (d^2\,\sqrt {b^2-4\,a\,c}-4\,c\,d\,e\right )\right )}{4\,a^3\,c\,d^4-a^2\,b^2\,d^4-8\,a^2\,b\,c\,d^3\,e+8\,a^2\,c^2\,d^2\,e^2+2\,a\,b^3\,d^3\,e+2\,a\,b^2\,c\,d^2\,e^2-8\,a\,b\,c^2\,d\,e^3+4\,a\,c^3\,e^4-b^4\,d^2\,e^2+2\,b^3\,c\,d\,e^3-b^2\,c^2\,e^4}-\frac {\ln \left (d+e\,x\right )\,\left (b\,e^2-2\,a\,d\,e\right )}{a^2\,d^4-2\,a\,b\,d^3\,e+2\,a\,c\,d^2\,e^2+b^2\,d^2\,e^2-2\,b\,c\,d\,e^3+c^2\,e^4}-\frac {\ln \left (c\,e^4\,{\left (b^2-4\,a\,c\right )}^{5/2}+8\,b^5\,c\,e^4+8\,b^6\,e^4\,x-4\,a^3\,d^4\,{\left (b^2-4\,a\,c\right )}^{3/2}+4\,a^3\,b^3\,d^4+4\,b^3\,e^4\,x\,{\left (b^2-4\,a\,c\right )}^{3/2}-60\,a\,b^3\,c^2\,e^4+112\,a^2\,b\,c^3\,e^4-4\,a\,b^5\,d^2\,e^2+8\,a^2\,b^4\,d^3\,e-256\,a^3\,c^3\,d\,e^3+256\,a^4\,c^2\,d^3\,e+8\,a^4\,b^2\,d^4\,x-32\,a^3\,c^3\,e^4\,x+10\,b\,d\,e^3\,{\left (b^2-4\,a\,c\right )}^{5/2}+4\,b\,e^4\,x\,{\left (b^2-4\,a\,c\right )}^{5/2}-16\,a^4\,b\,c\,d^4-32\,a^5\,c\,d^4\,x-14\,a\,d^2\,e^2\,{\left (b^2-4\,a\,c\right )}^{5/2}+7\,b^2\,c\,e^4\,{\left (b^2-4\,a\,c\right )}^{3/2}-10\,b^3\,d\,e^3\,{\left (b^2-4\,a\,c\right )}^{3/2}-8\,a\,d\,e^3\,x\,{\left (b^2-4\,a\,c\right )}^{5/2}-24\,a\,b^4\,c\,d\,e^3-64\,a\,b^4\,c\,e^4\,x-32\,a\,b^5\,d\,e^3\,x-8\,a^2\,b\,d^3\,e\,{\left (b^2-4\,a\,c\right )}^{3/2}-32\,a^3\,d^3\,e\,x\,{\left (b^2-4\,a\,c\right )}^{3/2}-96\,a^3\,b^2\,c\,d^3\,e-16\,a^3\,b^3\,d^3\,e\,x+18\,a\,b^2\,d^2\,e^2\,{\left (b^2-4\,a\,c\right )}^{3/2}+160\,a^2\,b^2\,c^2\,d\,e^3+56\,a^2\,b^3\,c\,d^2\,e^2-160\,a^3\,b\,c^2\,d^2\,e^2+136\,a^2\,b^2\,c^2\,e^4\,x+40\,a^2\,b^4\,d^2\,e^2\,x+448\,a^4\,c^2\,d^2\,e^2\,x+48\,a^2\,b\,d^2\,e^2\,x\,{\left (b^2-4\,a\,c\right )}^{3/2}-272\,a^3\,b^2\,c\,d^2\,e^2\,x+64\,a^4\,b\,c\,d^3\,e\,x-24\,a\,b^2\,d\,e^3\,x\,{\left (b^2-4\,a\,c\right )}^{3/2}+240\,a^2\,b^3\,c\,d\,e^3\,x-448\,a^3\,b\,c^2\,d\,e^3\,x\right )\,\left (e^2\,\left (\frac {b^3}{2}+\frac {b^2\,\sqrt {b^2-4\,a\,c}}{2}\right )-a\,\left (\left (2\,b\,c+c\,\sqrt {b^2-4\,a\,c}\right )\,e^2+\left (b^2\,d+b\,d\,\sqrt {b^2-4\,a\,c}\right )\,e\right )+a^2\,\left (d^2\,\sqrt {b^2-4\,a\,c}+4\,c\,d\,e\right )\right )}{4\,a^3\,c\,d^4-a^2\,b^2\,d^4-8\,a^2\,b\,c\,d^3\,e+8\,a^2\,c^2\,d^2\,e^2+2\,a\,b^3\,d^3\,e+2\,a\,b^2\,c\,d^2\,e^2-8\,a\,b\,c^2\,d\,e^3+4\,a\,c^3\,e^4-b^4\,d^2\,e^2+2\,b^3\,c\,d\,e^3-b^2\,c^2\,e^4}-\frac {e}{\left (d+e\,x\right )\,\left (a\,d^2-b\,d\,e+c\,e^2\right )} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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